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Class 8Algebra8:02Published 23 Apr 2025

How to Solve 3 Linear Equations in One Variable

Solve three linear equations in one variable that mix fractions and decimals, clearing denominators and using cross multiplication to reach the answer.

This lesson works through three linear equations in one variable, step by step. You start by taking the LCM to clear the fractions, expand the brackets carefully with attention to signs, and then use cross multiplication to remove the remaining denominators. Transposing terms and simplifying gives the solutions x = 2, m = 7/5, and f = 0.6. The third example also shows how to turn decimal coefficients into fractions before solving.

What you'll learn

  • Clearing fractions by multiplying through by the lowest common denominator
  • Expanding brackets carefully, watching the sign in front of each group
  • Using cross multiplication to solve an equation with a fraction on each side
  • Rewriting decimal coefficients as fractions before solving

Lesson chapters

0:00Why these equations matter
0:16Question 1: setting up and taking the LCM
2:18Question 1: cross multiplying to find x
4:03Question 2: an equation with brackets and signs
6:27Question 3: clearing decimal coefficients
8:01Final answer for f

Lesson notes

This lesson solves three linear equations in one variable. Each one has fractions or decimals, so the plan is the same every time: clear the denominators, expand carefully, then use cross multiplication to finish.

Question 1: an equation with fractions

We are given

3x242x+33=23x3.\frac{3x-2}{4} - \frac{2x+3}{3} = \frac{2-3x}{3}.

Left side. The lowest common denominator of 44 and 33 is 1212. Combining the two fractions over 1212:

3(3x2)4(2x+3)12.\frac{3(3x-2) - 4(2x+3)}{12}.

Expand the numerator, watching the sign on the second bracket:

9x68x1212=x1812.\frac{9x - 6 - 8x - 12}{12} = \frac{x - 18}{12}.

Cross multiplication. With a single fraction on each side, multiply each numerator by the other side's denominator:

3(x18)=12(23x).3(x - 18) = 12(2 - 3x).

3x54=2436x.3x - 54 = 24 - 36x.

Collect the xx terms on the left and the numbers on the right:

3x+36x=24+5439x=78.3x + 36x = 24 + 54 \quad\Longrightarrow\quad 39x = 78.

x=7839=2.x = \frac{78}{39} = 2.

Question 2: brackets and signs

We are given

mm12=1m23.m - \frac{m-1}{2} = 1 - \frac{m-2}{3}.

Left side. The LCD is 22:

2m(m1)2=2mm+12=m+12.\frac{2m - (m-1)}{2} = \frac{2m - m + 1}{2} = \frac{m + 1}{2}.

Right side. The LCD is 33:

3(m2)3=3m+23=5m3.\frac{3 - (m-2)}{3} = \frac{3 - m + 2}{3} = \frac{5 - m}{3}.

Cross multiplication.

3(m+1)=2(5m).3(m + 1) = 2(5 - m).

3m+3=102m.3m + 3 = 10 - 2m.

Transpose: move 2m-2m to the left and +3+3 to the right:

3m+2m=1035m=7.3m + 2m = 10 - 3 \quad\Longrightarrow\quad 5m = 7.

m=75.m = \frac{7}{5}.

Question 3: decimal coefficients

We are given

0.25(4f3)=0.05(10f9).0.25(4f - 3) = 0.05(10f - 9).

Write the decimals as fractions: 0.25=251000.25 = \tfrac{25}{100} and 0.05=51000.05 = \tfrac{5}{100}. Since both sides share the denominator 100100, it cancels, leaving

25(4f3)=5(10f9).25(4f - 3) = 5(10f - 9).

Expand both sides:

100f75=50f45.100f - 75 = 50f - 45.

Collect the ff terms on the left and the numbers on the right:

100f50f=45+7550f=30.100f - 50f = -45 + 75 \quad\Longrightarrow\quad 50f = 30.

f=3050=35=0.6.f = \frac{30}{50} = \frac{3}{5} = 0.6.

Key takeaways

  • Clear fractions first by multiplying through by the lowest common denominator, and keep each group in brackets.
  • When a minus sign sits in front of a bracket, it changes the sign of every term inside.
  • With one fraction on each side, cross multiply, then transpose and simplify to isolate the variable. Decimal coefficients can be rewritten as fractions to make this easier.