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Class 8Algebra4:02Published 18 Mar 2025

Multiplication of Algebraic Terms

Learn how to multiply algebraic terms by combining the sign rules, the numerical coefficients, and the laws of exponents, with several worked examples.

This lesson shows how to multiply two or more algebraic terms step by step. You first fix the sign using the rules for multiplying positive and negative numbers, then multiply the number coefficients, and finally combine like variables by adding their exponents. Worked examples build from a simple product of two terms up to a product of three terms with several variables.

What you'll learn

  • How the sign rules decide whether a product of terms is positive or negative
  • Multiplying the number coefficients of each term together
  • Adding the powers of the same variable when multiplying terms

Lesson chapters

0:00Sign rules and laws of exponents
0:49Example: two terms with x and y
1:44Example: three terms with p and q
2:16Example: three negative terms
3:04Example: terms with x, y and z

Lesson notes

This lesson covers how to multiply algebraic terms. The method is always the same: fix the sign, multiply the number coefficients, then add the exponents of each repeated variable.

Sign rules

When multiplying signed numbers, the sign of the product follows four rules:

(+)×(+)=+,()×()=+,(+)×()=,()×(+)=(+)\times(+) = +,\quad (-)\times(-) = +,\quad (+)\times(-) = -,\quad (-)\times(+) = -

Laws of exponents

Multiplying powers of the same base uses these two results:

am×an=am+na^{m}\times a^{n} = a^{m+n}

(am)n=amn\left(a^{m}\right)^{n} = a^{mn}

The first rule, adding exponents, is the one used throughout these examples.

Example 1: 8x2y×3xy28x^{2}y \times 3xy^{2}

Multiply the numbers, then group each variable.

8x2y×3xy2=(8×3)(x2×x)(y×y2)8x^{2}y \times 3xy^{2} = (8\times 3)\,(x^{2}\times x)\,(y\times y^{2})

Numbers: 8×3=248\times 3 = 24. Variable xx: x2+1=x3x^{2+1} = x^{3}. Variable yy: y1+2=y3y^{1+2} = y^{3}.

=24x3y3= 24x^{3}y^{3}

Example 2: 4pq×8p2q2×3p4pq \times 8p^{2}q^{2} \times 3p

4pq×8p2q2×3p=(4×8×3)p1+2+1q1+24pq \times 8p^{2}q^{2} \times 3p = (4\times 8\times 3)\,p^{1+2+1}\,q^{1+2}

Numbers: 4×8×3=964\times 8\times 3 = 96. Variable pp: p1+2+1=p4p^{1+2+1} = p^{4}. Variable qq: q1+2=q3q^{1+2} = q^{3}.

=96p4q3= 96p^{4}q^{3}

Example 3: (3x2y2)×(2x3y)×(4xy3)(-3x^{2}y^{2})\times(-2x^{3}y)\times(-4xy^{3})

First the sign: three negative factors give a negative product, since ()×()=+(-)\times(-) = + and then (+)×()=(+)\times(-) = -.

(3x2y2)(2x3y)(4xy3)=(3×2×4)x2+3+1y2+1+3(-3x^{2}y^{2})(-2x^{3}y)(-4xy^{3}) = -(3\times 2\times 4)\,x^{2+3+1}\,y^{2+1+3}

Numbers: 3×2×4=243\times 2\times 4 = 24. Variable xx: x2+3+1=x6x^{2+3+1} = x^{6}. Variable yy: y2+1+3=y6y^{2+1+3} = y^{6}.

=24x6y6= -24x^{6}y^{6}

Example 4: 800x3y2z×(2xy5z2)×1800x^{3}y^{2}z \times (-2xy^{5}z^{2}) \times 1

800x3y2z×(2xy5z2)×1=(800×(2)×1)x3+1y2+5z1+2800x^{3}y^{2}z \times (-2xy^{5}z^{2}) \times 1 = (800\times(-2)\times 1)\,x^{3+1}\,y^{2+5}\,z^{1+2}

Numbers: 800×(2)×1=1600800\times(-2)\times 1 = -1600. Variable xx: x3+1=x4x^{3+1} = x^{4}. Variable yy: y2+5=y7y^{2+5} = y^{7}. Variable zz: z1+2=z3z^{1+2} = z^{3}.

=1600x4y7z3= -1600x^{4}y^{7}z^{3}

Key takeaways

  • The sign of a product is positive when there is an even number of negative factors and negative when there is an odd number.
  • Multiply the numerical coefficients of all the terms together.
  • For each variable, add the exponents from every term in which it appears.